Consider the inverted slider-crank linkage as shown in the following figure. Given are: . Link lengths: Link 1 = 1.2 m, Link 2 = 0.5 m, Link 4 = 0.9 m. • Positions: y = 90°, 02 = 75°, 03 = 205.74°, 04 = 115.74°, b = BA = 0.755 m. Angular velocities: 002 = +10 rad/s (CCW), 003 004 = -4.32 rad/s (CW) Velocity of slip:b = 7.68 m/s • Angular acceleration of link 2: a2 = 100 rad/s CCW. a) Calculate the angular acceleration of links 4 and 3 and the acceleration of slip at point B b) Calculate the magnitude and direction of the acceleration of point A 02 1 B 04 84 X Consider the inverted slider-crank linkage as shown in the following figure. Given are: • Link lengths: Link O2A = 10 cm, Link O4B = 15 cm, Link O2O4 = 20 cm. Positions: y 90°, 02 = 140°, 03 = 198.8°, 04 = 108.8°, b = AB = 24.113 cm. Angular velocities: 2 = -15 rad/s (CW), 003 = 004 = -3.22 rad/s (CW) Velocity of slip: b = -80 cm/s • • Link O2A rotates with a constant angular velocity. a) Calculate the angular acceleration of links 4 and 3 and the acceleration of slip at point B. b) Calculate the magnitude and direction of the acceleration of point B. Y 03 A Y 02 02 B X Ꮎ X 04

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A: hope this will help. feel free to ask if you need anything more. Thank You.

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