Chapter 3, Problem 1E

Question

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Answer 1

Question

Chapter 3, Problem 1E

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

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Answer 2

Question

Chapter 3, Problem 1E

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

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Answer 3

Question

Chapter 3, Problem 1E

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

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Answer 4

Question

Chapter 3, Problem 1E

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

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Answer 5

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Answer 6

a)

Expert Solution

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Answer 7

a)

Expert Solution

Answer 8

a)

Expert Solution

Answer 9

Expert Solution

Answer 10

To determine

The amount of radiation emitted from the surface of the Sun, given the average surface temperature of Sun is 6000 K.

Answer 11

Answer to Problem 1E

The radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Answer 12

Explanation of Solution

Electromagnetic energy is radiated from the Sun, and it reaches the surface of the Earth in the form of visible radiations. Initially, the spectrum contains all types of wavelengths, and the atmosphere filters out certain wavelengths.

The emission of radiation by a body can be understood from Stefan–Boltzmann law. This law states, “Energy emitted by a body is directly proportional to the fourth power of temperature”.

E∝T4E=σT4

Here, E is the energy emitted by a body, T is the temperature of the body, and σ is the Stefan–Boltzmann constant

The formula to calculate the radiation emitted by the Sun at 6,000K is expressed below:

E=σT4

Substitute 5.67×10−8 Wm−2K−4 for σ and 6000 K for T to find the radiation emitted by the Sun at 6,000K.

E=(5.67×10−8 Wm−2K−4)(6,000 K)4=73,483,200 Wm−2

Therefore, the radiation emitted by the Sun at 6000K is 73,483,200 Wm−2.

Answer 13

b)

Expert Solution

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Answer 14

b)

Expert Solution

Answer 15

b)

Expert Solution

Answer 16

Expert Solution

Answer 17

To determine

The amount of radiation emitted from the Earth’s surface at 300 K.

Answer 18

Answer to Problem 1E

The radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Answer 19

Explanation of Solution

Refer to subpart ‘a’ for description regarding Stefan–Boltzmann law.

The formula to calculate the radiation emitted by the Earth’s surface at 300K is expressed below:

E=σT4

To find the radiation emitted by the Earth’s surface at 300K, substitute 5.67×10−8 Wm−2K−4 for σ and 300 K for T.

E=(5.67×10−8 Wm−2K−4)(3,00 K)4=459.27 Wm−2

Therefore, the radiation emitted by the Earth’s surface at 300K is 459.27 Wm−2.

Answer 20

Chapter 3, Problem 1E Chapter 3, Problem 2E Chapter 3, Problem 3E Chapter 3, Problem 4E Chapter 3, Problem 5E Chapter 3, Problem 6E Chapter 3, Problem 7E Chapter 3, Problem 8E Chapter 3, Problem 9E Chapter 3, Problem 10E

Chapter 3, Problem 1E

Answer to Problem 1E

Explanation of Solution

Answer to Problem 1E

Explanation of Solution

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